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Free CWAP-405 practice test: 30 questions with answers

30 original questions for Certified Wireless Analysis Professional (CWAP), drawn from every topic area. Answer each one to see whether you got it right and why. No sign-up.

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CWAP-405 exam guide: topics, cost and format

All 30 CWAP-405 questions with answers

The same questions as the test above, grouped by exam topic. Open any question to see the answer and explanation.

802.11 Frame Exchanges (5 questions)

  1. Question 1

    During a client's join to an AP, the capture shows an Authentication exchange followed by an Association Request. Which frame from the AP completes the association and assigns the client its association identifier?

    1. AProbe Response, which lists the supported rates and the channel the AP is using
    2. BReassociation Response, which moves the client's state from a previous AP to this one
    3. CAssociation Response, which carries the status code and the association identifier
    4. DBeacon, which announces the BSS parameters and the traffic indication map to all stations
    Show answer and explanation
    Correct answer: C

    The AP answers an Association Request with an Association Response that carries a status code and the AID for the client. A Probe Response answers active scanning, a Reassociation Response is used when a client moves from another AP, and a Beacon is a periodic broadcast that does not complete a join.

  2. Question 2

    A client roams from AP-1 to AP-2 in the same ESS. The capture shows a Reassociation Request that includes the address of AP-1. Why does the client include that address?

    1. ASo AP-2 can contact AP-1 through the distribution system to hand over client context and buffered frames
    2. BSo AP-1 knows to send a deauthentication frame to the client's old session
    3. CSo AP-2 can borrow AP-1's beacon interval for timing, which the roaming protocol requires for synchronization between the two APs
    4. DSo the client can ask AP-1 for a fresh IP address through the DHCP relay on its uplink
    Show answer and explanation
    Correct answer: A

    The Current AP Address field lets the new AP reach the previous AP across the distribution system, so client state and buffered frames can be transferred. The other options misdescribe the field: deauthentication is not triggered this way, timing comes from each AP's own beacons, and IP addressing is handled by DHCP rather than by the reassociation frame.

  3. Question 3

    Which amendment reduces the time a client spends in the key exchange when it roams between APs that share the same mobility domain?

    1. A802.11k, which provides neighbor reports so the client can scan only a short list of likely channels when it roams
    2. B802.11r, Fast BSS Transition, which lets the client reuse key material within the mobility domain
    3. C802.11v, which lets the network send BSS transition management suggestions to clients
    4. D802.11w, which protects selected management frames against forgery and replay attacks
    Show answer and explanation
    Correct answer: B

    Fast BSS Transition (802.11r) lets the client reuse key material within the mobility domain, so the roam needs a shorter key exchange. 802.11k, 802.11v and 802.11w address neighbor reports, transition suggestions and management frame protection rather than fast key setup.

  4. Question 4

    An A-MPDU burst is sent to an AP, and the AP answers with one Block Ack frame. The analyst sees that some MPDUs are marked as missing in the bitmap. What does the sender do with them?

    1. ARepeats the entire burst, because a Block Ack frame cannot indicate which individual frames were lost in transit
    2. BRetransmits only the MPDUs the bitmap marks as not received, and keeps the rest of the burst
    3. CDrops the missing MPDUs silently, since the Block Ack bitmap reports only the TXOP length
    4. DSends a deauthentication frame and rejoins the BSS before sending any retransmissions
    Show answer and explanation
    Correct answer: B

    The Block Ack bitmap reports which MPDUs in the burst were received correctly, so the sender retransmits only the missing ones. Repeating the whole burst, rejoining the BSS or dropping frames silently do not match how Block Ack works, and the bitmap does not describe TXOP length.

  5. Question 5

    An 802.11ax AP wants several stations to send uplink data in the same time window, each on its own resource unit. Which frame does the AP send to schedule that uplink transmission?

    1. ANDP Announcement frame, which tells the stations that a sounding sequence is about to start so they can prepare feedback
    2. BBlock Ack Request frame, which asks a single station to confirm received MPDUs
    3. CTrigger frame, which allocates resource units and solicits the uplink responses
    4. DAction frame carrying a group identifier used for multi-user beamforming
    Show answer and explanation
    Correct answer: C

    A Trigger frame from the AP defines which stations send, on which resource units and when, so that OFDMA uplink responses arrive together. An NDP Announcement starts channel sounding, a Block Ack Request asks for acknowledgment state, and an Action frame with a group identifier does not schedule uplink transmissions.

MAC Sublayer and Functions (5 questions)

  1. Question 6

    An analyst sees one QoS data frame whose body contains several subframes, each with its own length, and only one MAC header and one FCS covering the whole payload. Which aggregation method does this describe?

    1. ABlock Ack, which acknowledges a burst of frames with a single bitmap response
    2. BA-MPDU, which places several complete MPDUs with their own headers into one PPDU
    3. CFragmentation, which splits one MSDU into several MPDUs for a noisy channel
    4. DA-MSDU, which packs several MSDUs under one MAC header and one FCS
    Show answer and explanation
    Correct answer: D

    A-MSDU packs multiple MSDUs into one MPDU that has a single MAC header and FCS. A-MPDU carries multiple complete MPDUs that each have their own header and FCS, Block Ack is an acknowledgment method, and fragmentation splits one MSDU rather than combining several.

  2. Question 7

    Which MAC header field lets a receiver detect duplicate frames that were retransmitted after a lost acknowledgment?

    1. AThe Duration/ID field, which carries the time that the medium is reserved for the remainder of the frame exchange
    2. BThe Address 4 field, which is used only in wireless distribution system frames
    3. CThe Sequence Control field, which holds the sequence number used for duplicate detection
    4. DThe Frame Control subtype field, which identifies the purpose of the management frame
    Show answer and explanation
    Correct answer: C

    Each MSDU or MPDU carries a sequence number, and a retransmitted frame keeps its original sequence number, so the receiver can discard the duplicate. The Duration/ID field reserves airtime, Address 4 appears only in certain WDS frames, and the subtype identifies the frame type rather than duplicates.

  3. Question 8

    A capture shows a unicast data frame with the Retry bit set. Its sequence number matches an earlier frame from the same station that was sent a few milliseconds before. What is the most likely explanation?

    1. AThe station is sending a broadcast frame that all stations in the BSS must process once
    2. BThe station is moving to a new BSS and is sending the frame as part of a reassociation
    3. CThe station is retransmitting a frame because it did not receive the expected acknowledgment
    4. DThe station is sending the next fragment of a larger MSDU, which carries a new fragment number
    Show answer and explanation
    Correct answer: C

    The Retry bit marks a retransmission, and retransmissions keep the sequence number of the original frame. Broadcast frames are not acknowledged or retried, reassociation is a separate management exchange, and a new fragment would carry a different fragment number.

  4. Question 9

    A receiver computes the FCS on an incoming unicast frame and finds that it does not match. What does the receiver do, and what happens next at the sender?

    1. AIt sends a NAK frame at once, so the sender retransmits immediately without waiting for its acknowledgment timer to expire
    2. BIt forwards the damaged frame up the stack with a flag, and the sender sends no further data
    3. CIt sends an ACK so the sender stops, and the upper layers request the missing data later
    4. DIt discards the frame without sending an ACK, so the sender retransmits after its acknowledgment timeout
    Show answer and explanation
    Correct answer: D

    A frame that fails the FCS check is not acknowledged, so the sender waits for the ACK timer and retransmits, up to its retry limit. 802.11 has no NAK frame, damaged frames are not passed up the stack, and an ACK for a bad frame would falsely tell the sender that it was received.

  5. Question 10

    A station sends an A-MSDU that carries four MSDUs inside one MPDU. The receiver reports that the MPDU failed its FCS check. An analyst asks what the sender will retransmit. Which answer is correct?

    1. AThe entire A-MSDU, because a single FCS covers all of its subframes
    2. BOnly the subframe whose destination address is in the failing MPDU header
    3. COnly the first MSDU, since it carries the sequence number for the aggregate
    4. DNothing, because aggregated frames are protected by per-subframe checksums that repair errors
    Show answer and explanation
    Correct answer: A

    An A-MSDU is one MPDU with one FCS, so a failed check invalidates all of its subframes and the sender retransmits the whole unit. Subframes have no separate FCS, the sequence number does not isolate a single subframe, and aggregated frames are not repaired in place.

Protocol Analysis (5 questions)

  1. Question 11

    A network engineer must find out why a client's WPA2-Personal authentication keeps failing at one access point. The engineer plans to use a laptop with a Wi-Fi adapter for the capture. Which adapter mode and setup is required to see the management and EAPOL frames exchanged between the client and that access point?

    1. AManaged mode associated to the same SSID, since the adapter only receives frames addressed to its own MAC address and broadcasts
    2. BCapture on the controller's wired uplink only, since all wireless management frames are forwarded there
    3. CPromiscuous mode on the wired interface that connects to the access point's uplink switch port
    4. DMonitor mode on the adapter tuned to the channel used by the access point, so frames between other stations are received
    Show answer and explanation
    Correct answer: D

    Monitor mode on a radio tuned to the BSS channel receives 802.11 management and data frames exchanged between other stations and the AP. Managed mode passes only frames for the adapter's own address, and wired captures never carry 802.11 management frames or EAPOL exchanges, which stop at the AP.

  2. Question 12

    Which limitation applies to one 802.11 capture adapter that is tuned to a single channel?

    1. AIt sees only frames sent on the channel it is tuned to, so traffic on other channels is missed
    2. BIt decrypts WPA3-protected data frames automatically as long as the adapter is in monitor mode
    3. CIt receives every channel in the same band at once through its single radio
    4. DIt captures traffic from neighboring networks only when they share the adapter's configured SSID
    Show answer and explanation
    Correct answer: A

    A radio receives on one channel at a time, so a capture on one channel cannot see frames sent on other channels. Monitor mode does not supply decryption keys, so encrypted data stays unreadable without them, and an adapter does not select traffic by SSID.

  3. Question 13

    An analyst must monitor two access points on different channels during the same troubleshooting window. The team has only one capture adapter. What is the most reliable way to capture both sides of the conversation?

    1. ASwitch the single adapter between the two channels every few seconds and merge the resulting traces
    2. BUse two capture adapters or sensors, one per channel, with synchronized clocks so the traces can be merged
    3. CCapture on the wired switch port of one access point and infer the other traffic from frame counts
    4. DSet the adapter to a 20 MHz width on both channels so the single radio can cover both channels at the same time without retuning
    Show answer and explanation
    Correct answer: B

    Two capture points, each tuned to one channel, record every frame on both channels, and synchronized timestamps let the traces be aligned. Hopping one radio misses frames while it is away, a 20 MHz setting does not let a single radio cover two separate channels, and a wired capture never contains the other AP's wireless frames.

  4. Question 14

    Which two items must be available so that Wireshark can decrypt captured WPA2-Personal data frames? (Choose two.)

    1. AThe network passphrase, which is combined with the SSID to derive the pairwise master key
    2. BThe four-way handshake captured when the client joined the network
    3. CThe BSSID and channel number advertised in the beacon frames
    4. DThe RADIUS shared secret that the access point uses to reach the authentication server
    Show answer and explanation
    Correct answer: A, B

    Decryption needs the passphrase (with the SSID) to derive the PMK, and the captured four-way handshake to derive the session keys. Beacon fields are not secrets, and a RADIUS shared secret belongs to 802.1X networks, while WPA2-Personal has no RADIUS server.

  5. Question 15

    A voice call shows jitter in a wired packet capture taken on a server. The analyst also has a wireless capture from a laptop on the same call and wants to line up the two traces packet by packet. What is the most important prerequisite?

    1. ABoth captures must use the same radiotap header version so that every field in the two traces lines up correctly
    2. BBoth traces must contain identical MAC addresses in every frame for matching
    3. CThe wireless capture must be taken with the adapter set to the wired MTU size
    4. DBoth capture devices must have clocks synchronized, such as through NTP, so timestamps are comparable
    Show answer and explanation
    Correct answer: D

    Synchronized timestamps let frames from two different capture points be placed on one timeline. Radiotap header versions, MTU settings and matching MAC addresses do not establish timing between separate captures.

Spectrum Analysis (5 questions)

  1. Question 16

    A 2.4 GHz network loses throughput every few minutes. A spectrum view shows a broad, bursty signal that appears only while the kitchen microwave runs and fades when it stops. Which conclusion is best supported?

    1. AA Bluetooth headset is hopping across the band and causing frame errors on the WLAN
    2. BA neighboring access point is transmitting on the same channel and causing co-channel contention
    3. CA rogue client is sending deauthentication frames to the access point at fixed intervals
    4. DA microwave oven is leaking broadband energy into the 2.4 GHz band and degrading nearby channels
    Show answer and explanation
    Correct answer: D

    Microwave ovens emit broadband interference in the 2.4 GHz band that is tied to the appliance's on-time, which matches the spectrum pattern. A neighboring AP would appear as decodable 802.11 frames, Bluetooth hops are not tied to a kitchen appliance, and deauthentication frames are protocol traffic that a spectrum view cannot show.

  2. Question 17

    What does a centralized spectrum analysis system add compared with a single sensor that monitors one area?

    1. AIt decodes 802.11 data frames so that each client's traffic can be billed to a department
    2. BIt aggregates RF data from distributed sensors into one view for finding interference across the site
    3. CIt replaces the wireless controller's channel plan with a fixed channel assignment for every AP in the building
    4. DIt stores all client data frames at a single point so that the APs no longer need to buffer traffic
    Show answer and explanation
    Correct answer: B

    A central system combines measurements from many sensors, so interference sources can be compared across the whole site. Decoding client traffic for billing, replacing the channel plan and centralizing frame buffering are not the purpose of spectrum analysis, which looks at RF energy rather than client data.

  3. Question 18

    An engineer wants to see how an interferer's energy on one 5 GHz channel changes minute by minute, so that a repeating pattern becomes visible. Which spectrum view is the most useful?

    1. AA waterfall view that plots frequency across one axis and time down the other, so repeating bursts stand out
    2. BA single peak-amplitude snapshot taken at the moment the engineer opens the spectrum tool and reads the highest reading
    3. CA pie chart of the percentage of each channel's frames that are management frames
    4. DA table of decoded SSIDs and their signal levels, sorted by the strongest beacon on the channel
    Show answer and explanation
    Correct answer: A

    A waterfall (spectrogram) view adds time as a dimension, so periodic interference appears as repeating patterns. A single snapshot shows one instant, a frame-type pie chart is a protocol statistic rather than an RF view, and a decoded SSID table cannot show non-802.11 energy.

  4. Question 19

    A spectrum view shows short, narrow bursts that jump rapidly from one frequency to another across the 2.4 GHz band, with no fixed center frequency. Which device type does this pattern most likely indicate?

    1. AA frequency-hopping device such as a Bluetooth headset, which changes channel many times per second
    2. BA video camera whose wireless link stays on one channel and sends a constant bit rate stream
    3. CA microwave oven, which produces a broadband signal tied to its on-time rather than a series of narrow hops
    4. DA neighboring access point on a fixed channel that transmits beacons at a steady interval and carries no hopping pattern at all
    Show answer and explanation
    Correct answer: A

    Frequency hopping spreads a device's short bursts across the band, and Bluetooth is a common hopping device in 2.4 GHz. A microwave oven produces a broadband signal tied to its on-time, while a fixed-channel camera or access point does not change frequency in this way.

  5. Question 20

    A 5 GHz channel shows high utilization on the spectrum view, but the protocol analyzer decodes few 802.11 frames in the same window, and the energy trace has no frame-shaped bursts. What is the most likely explanation?

    1. AChannel utilization is calculated only from decoded frames, so the high figure must be a reporting error in the tool
    2. BThe channel is busy with energy the analyzer cannot decode as 802.11, such as non-Wi-Fi interference
    3. CThe access points are sending Probe Requests at a rate the analyzer cannot display, so those frames never reach the trace
    4. DThe clients are in power save mode, which raises channel utilization while they send no frames at all
    Show answer and explanation
    Correct answer: B

    Channel utilization on a spectrum view reflects energy and busy time, so non-802.11 sources can make a channel look busy while few decodable frames appear. Utilization is not calculated only from decoded frames, power save reduces transmissions rather than raising utilization, and Probe Requests come from clients rather than APs.

PHY Layers and Technologies (5 questions)

  1. Question 21

    A capture shows a legacy preamble at the start of an 802.11n PPDU. A non-HT 802.11a/g station is nearby and needs to know how long the PPDU lasts so it can defer. Which field gives that information?

    1. AThe L-SIG field, which carries the rate and length in a form legacy stations can decode
    2. BThe VHT-SIG-A field, which carries the bandwidth and group identifiers for 802.11ac
    3. CThe HT-SIG field, which carries the modulation and coding details for HT stations only
    4. DThe short training field, which sets automatic gain control and timing for the receiver
    Show answer and explanation
    Correct answer: A

    L-SIG sits in the legacy preamble and is sent in a format that non-HT stations can decode, so they can compute the PPDU duration and defer. HT-SIG and VHT-SIG-A are read only by newer stations, and the training fields serve receiver timing rather than telling a legacy station how long to defer.

  2. Question 22

    What is the purpose of a pseudo-header, such as the radiotap header, in an 802.11 capture file?

    1. AIt carries the encryption keys needed to decrypt the frames that follow it
    2. BIt replaces the 802.11 MAC header so that the captured frame can be routed onward on a wired network segment
    3. CIt records radio metadata such as signal level, data rate and channel for each captured frame
    4. DIt holds the frame check sequence that the receiver uses to verify the over-the-air frame
    Show answer and explanation
    Correct answer: C

    Pseudo-headers are added by the capture tool, not sent over the air, and they describe the radio conditions under which the frame was received. Keys, MAC header replacement and FCS values are not the job of a pseudo-header, and the FCS stays part of the 802.11 frame itself.

  3. Question 23

    An engineer buys a USB capture adapter that supports only 802.11g rates. The team then needs to capture traffic from an 802.11ac network. What problem should the team expect?

    1. AThe adapter captures every frame but loses only the management frames, which Wireshark rebuilds
    2. BThe adapter cannot decode VHT PPDUs, so frames from the 802.11ac BSS are missed or unreadable
    3. CThe adapter can capture the 802.11ac traffic in full once it is set to the 2.4 GHz band
    4. DThe adapter will capture the data frames but cannot record the signal strength field
    Show answer and explanation
    Correct answer: B

    Decoding a PPDU requires an adapter that understands its PHY format, and an 802.11g-only radio cannot decode the VHT transmissions of an 802.11ac network. The other options describe partial or incorrect capture behaviour, such as losing only management frames or switching to a band the 5 GHz network does not use.

  4. Question 24

    An analyst opens an 802.11ac PPDU in a decoder. Which portion carries the MAC frame, such as a data frame or management frame, that the station needs to process?

    1. AThe legacy short training field, which provides timing and gain control for the receiver
    2. BThe VHT-SIG-A field, which describes the bandwidth, group identifier and number of spatial streams
    3. CThe PLCP preamble, which lets the receiver detect that a transmission has started
    4. DThe PSDU, which is the payload that holds the MPDU or aggregate
    Show answer and explanation
    Correct answer: D

    The PSDU is the payload portion of a PPDU and carries the MPDU or A-MPDU that holds the MAC frame. The training fields, SIG fields and preamble are PHY-layer overhead that synchronize the receiver or describe the transmission rather than carry the MAC frame.

  5. Question 25

    What is the main benefit of the optional short preamble in 802.11b DSSS transmissions?

    1. AIt increases transmit power on the 2.4 GHz band, which extends the coverage area of the cell
    2. BIt allows older 802.11a stations, which use OFDM rather than DSSS, to decode the frame without any legacy preamble at all
    3. CIt lowers preamble overhead, so more of each transmission time carries payload at higher DSSS rates
    4. DIt replaces the frame check sequence, so the receiver does not need to verify each frame
    Show answer and explanation
    Correct answer: C

    The short preamble is shorter than the long one, so it takes less airtime and leaves more of each DSSS transmission for payload. It does not add transmit power or change how 802.11a stations work, and it never removes the FCS, which stays in every MAC frame.

WLAN Medium Access (5 questions)

  1. Question 26

    Two stations in the same BSS collide again and again while contending for the medium under DCF. Each collision makes the stations wait longer before the next attempt. What happens to the contention window after each collision?

    1. AIt doubles, up to the configured maximum, which spreads out the random backoff choices
    2. BIt is halved, so the stations retry sooner and reduce the wasted airtime
    3. CIt stays at the minimum value, because the backoff is reset by each acknowledgment and no later collision changes it
    4. DIt is replaced by a fixed slot count that every station uses on every retry
    Show answer and explanation
    Correct answer: A

    DCF uses binary exponential backoff, so the contention window doubles after each failed attempt until it reaches its maximum, which reduces repeated collisions. Halving or keeping the window at its minimum would increase collisions, and DCF does not use a fixed slot count.

  2. Question 27

    A WMM-enabled AP uses default EDCA parameters. Among the four access categories, which one has the highest priority for medium access, so that it usually wins contention first?

    1. AAC_VO, the voice category that carries the most delay-sensitive traffic
    2. BAC_BE, the best-effort category used by most ordinary data traffic
    3. CAC_VI, the video category that carries time-sensitive but less delay-critical streams
    4. DAC_BK, the background category used for bulk transfers that can tolerate delay
    Show answer and explanation
    Correct answer: A

    Under default EDCA values, AC_VO has the smallest contention window, so voice wins contention most often. AC_VI, AC_BE and AC_BK receive progressively longer waits and suit video, best-effort and background traffic.

  3. Question 28

    Which two mechanisms let a station defer transmission when it cannot hear a hidden station directly? (Choose two.)

    1. AThe NAV set from the Duration field of frames overheard from other stations
    2. BThe RTS/CTS exchange, whose CTS frame carries a duration that other stations use to set their NAV
    3. CPhysical carrier sense through clear channel assessment on the local radio
    4. DThe ACK retry counter that limits how many times a station resends a lost frame
    Show answer and explanation
    Correct answer: A, B

    Virtual carrier sense uses the Duration values in overheard frames, including CTS frames from an RTS/CTS exchange, to set the NAV and defer. Physical carrier sense only detects energy the station can hear, which does not help with hidden stations, and the retry counter has nothing to do with deferral.

  4. Question 29

    A unicast data frame has just finished, and the receiver must return an ACK. Which interframe space does the receiver use before sending the ACK?

    1. APIFS, which is reserved for beacon transmission, so it cannot be used for an ACK
    2. BThe EDCA AIFS value of the AC_BK category, which is the longest spacing of all
    3. CSIFS, the shortest spacing, which gives the response priority over contending stations
    4. DDIFS, the spacing that every station waits before starting a new contention for the medium
    Show answer and explanation
    Correct answer: C

    An ACK follows a unicast frame after a SIFS, the shortest interframe space, so the response goes out before other stations can contend. PIFS is not reserved for beacons, DIFS is the wait before a new contention, and the AC_BK AIFS governs contention rather than ACK spacing.

  5. Question 30

    Two APs on the same channel are close together. A station near AP-1 can hear AP-2's transmissions, but its own transmission would not interfere with AP-2's client. The station keeps deferring to AP-2's traffic and its throughput drops. Which problem is this?

    1. AThe exposed node problem, where a station defers to a transmission it does not need to avoid
    2. BThe hidden node problem, where a station cannot hear a transmitter that would collide with its frames
    3. CA NAV overflow, where the Duration field is larger than the maximum value allowed in the header
    4. DA retry storm caused by Block Ack frames that are not acknowledged by the receiving station
    Show answer and explanation
    Correct answer: A

    The exposed node problem occurs when a station defers to a transmission that its own frames would not disrupt, which lowers throughput. The hidden node problem is the reverse, a collision the sender cannot hear, while a NAV overflow and Block Ack retry storms are not the cause described.